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प्रश्न
If lines `(x - 1)/2 = (y + 1)/3 = (z - 1)/4` and x – 3 = `(y - k)/2` = z intersect then the value of k is ______.
विकल्प
`9/2`
`1/2`
`5/2`
`7/2`
MCQ
रिक्त स्थान भरें
उत्तर
If lines `(x - 1)/2 = (y + 1)/3 = (z - 1)/4` and x – 3 = `(y - k)/2` = z intersect then the value of k is `underlinebb(9/2)`.
Explanation:
Points on the given lines are respectively (1, –1, 1) and (3, k, 0) and their direction ratios are respectively 2, 3, 4 and 1, 2, 1
Since lines intersect, then lines are coplanar
∴ `|(x_2 - x_1, y_2 - y_1, z_2 - z_1),(a_1, b_1, c_1),(a_2, b_2, c_2)|` = 0
∴ `|(2, k + 1, -1),(2, 3, 4),(1, 2, 1)|` = 0
∴ 2(–5) – (k + 1)(–2) – 1(1) = 0
– 11 + 2k + 2 = 0
k = `9/2`
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