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प्रश्न
If m2 = -2 and n = 2; find the values of: 6m-3 + 4n2
योग
उत्तर
6m-3 + 4n2
m = - 2, n =2
= 6(-2)-3 + 4(2)2
`= 6 xx 1/-2 xx 1/-2 xx 1/-2 + 4 xx 2 xx 2`
`= (-3)/4 + 16`
`= (-3+16 xx4)/4 = (-3 + 64)/4 = 61/4 = 15 1/4`
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