Advertisements
Advertisements
प्रश्न
If numbers n – 2, 4n – 1 and 5n + 2 are in A.P., find the value of n and its next two terms.
उत्तर
Since (n – 2), (4n – 1) and (5n + 2) are in A.P., we have
(4n – 1) – (n – 2) = (5n + 2) – (4n – 1)
`\implies` 4n – 1 – n + 2 = 5n + 2 – 4n + 1
`\implies` 3n + 1 = n + 3
`\implies` 2n = 2
`\implies` n = 1
∴ (n – 2), (4n – 1) and (5n + 2)
∴ (1 – 2), (4(1) – 1) and (5(1) + 2)
So, the given numbers are –1, 3, 7
`\implies` a = –1 and d = 3 – (–1) = 4
Hence, the next two terms are (7 + 4) and (7 + 2 × 4)
i.e 11 and 15
APPEARS IN
संबंधित प्रश्न
Find the sum of first 8 multiples of 3
If (m + 1)th term of an A.P is twice the (n + 1)th term, prove that (3m + 1)th term is twice the (m + n + 1)th term.
Find the 12th term from the end of the following arithmetic progressions:
3, 5, 7, 9, ... 201
Three numbers are in A.P. If the sum of these numbers is 27 and the product 648, find the numbers.
The 4th term of an AP is 11. The sum of the 5th and 7th terms of this AP is 34. Find its common difference
Simplify `sqrt(50)`
If Sn denote the sum of the first n terms of an A.P. If S2n = 3Sn, then S3n : Sn is equal to
The given terms are 2k + 1, 3k + 3 and 5k − 1. find AP.
Find the value of x, when in the A.P. given below 2 + 6 + 10 + ... + x = 1800.
Assertion (A): a, b, c are in A.P. if and only if 2b = a + c.
Reason (R): The sum of first n odd natural numbers is n2.