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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

If P(A) = 23, P(B) = 25, P(A ∪ B) = 13, then find P(A ∩ B) - Mathematics

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प्रश्न

If P(A) = `2/3`, P(B) = `2/5`, P(A ∪ B) = `1/3`, then find P(A ∩ B)

योग

उत्तर

P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

`1/3 = 2/3 + 2/5 - "P"("A" ∩ "B")`

P(A ∩ B) = `2/3 + 2/5 - 1/3`

⇒ `(10 + 6 - 5)/15`

P(A ∩ B) = `11/15`

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Algebra of Events
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Statistics and Probability - Exercise 8.4 [पृष्ठ ३३०]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 8 Statistics and Probability
Exercise 8.4 | Q 1 | पृष्ठ ३३०
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