Question

If `sin^-1x + cos^-1y = (3pi)/10,` then `cos^-1x + sin^-1y =` ______ 

विकल्प

• `(2pi)/10`

• `(7pi)/10`

• `(9pi)/10`

• `(3pi)/10`

Answer 1

If `sin^-1x + cos^-1y = (3pi)/10,` then `cos^-1x + sin^-1y` = `underline((7pi)/10)`.

Explanation:

`sin^-1x + cos^-1y = (3pi)/10`

⇒ `pi/2 - cos^-1x + pi/2 - sin^-1y = (3pi)/10`

⇒ `pi - cos^-1x - sin^-1y = (3pi)/10`

⇒ `cos^-1x + sin^-1y = pi - (3pi)/10`

= `(7pi)/10`