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प्रश्न
If the density of oxygen is 1.44 kg/m3 at a pressure of 105 N/m2, find the root mean square velocity of oxygen molecules.
योग
उत्तर
Data: ρ = 1.44 kg/m3, P = 105 N/m2
∴ The root mean square velocity of oxygen molecules,
`"v"_"rms" = sqrt("3P"/rho) = sqrt((3xx10^5)/1.44)` m/s
`= sqrt(2.083 xx 10^5) = sqrt(20.83 xx 10^4)`
= 4.564 × 102 m/s
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