Advertisements
Advertisements
प्रश्न
If the difference between the sides of a right-angled triangle is 3 cm and its area is 54 cm2; find its perimeter.
उत्तर
Let the two sides be x cm and ( x - 3 ) cm.
Now,
`1/2 xx x xx ( x - 3 )` = 54
x2 - 3x - 108 = 0
( x - 12 )( x + 9 ) = 0
x = 12 cm
Hence the sides are 12 cm, 9 cm and `sqrt( 12^2 + 9^2)` = 15 cm.
The required perimeter is 12 + 9 + 15 = 36 cm.
APPEARS IN
संबंधित प्रश्न
The area of an equilateral triangle is `144sqrt3` cm2; find its perimeter.
Use the information given in the adjoining figure to find :
(i) the length of AC.
(ii) the area of an ∆ABC
(iii) the length of BD, correct to one decimal place.
Find the area of a triangle whose sides are 27 cm, 45 cm and 36 cm.
The perimeter of a triangle is 72cm and its sides are in the ratio 3:4:5. Find its area and the length of the altitude corresponding to the longest side.
Find the area of a triangle with a base 12cm and a height equal to the width of a rectangle having area of 96cm2 and a length of 12cm.
Find the perimeter of the triangle, whose sides are 13 cm, 5 cm and 14 cm
In the given figure, all triangles are equilateral and AB = 8 units. Other triangles have been formed by taking the mid points of the sides. What is the perimeter of the figure?
Two sides of a triangle are 12 cm and 14 cm. The perimeter of the triangle is 36 cm. What is its third side?
In the given figures, perimeter of ΔABC = perimeter of ΔPQR. Find the area of ΔABC.
Area of an isosceles triangle is 48 cm2. If the altitudes corresponding to the base of the triangle is 8 cm, find the perimeter of the triangle.
