Question

If the mean of observations x₁, x₂, x₃, ....x_n is `barx,` then the mean of new observations x₁ + a, x₂ + a, x₃ + a, ........ x_n + a is?

विकल्प

• `abarx`

• `barx+a`

• `barx-a`

• `barx/a`

Answer 1

`barx+a`

Explanation:-

We have

`barx=(x_1+x_2+x_3.......+x_n)/n   .........(i)`

`"New mean"=(x_1+a+x_2+a+x_3+a+........+x_n+a)/n`

`=>"New Mean"=(x_1+x_2+x_3+.......+x_n)/n+(a+a+a.....n "times")/n`

`=>"New Mean=barx+(na)/n"`     ...(from i)

⇒ New Mean = `barx+a`