हिंदी

If the parabola y2 = 4ax passes through the point (3, 2), then the length of its latus rectum is ______. - Mathematics

Advertisements
Advertisements

प्रश्न

If the parabola y2 = 4ax passes through the point (3, 2), then the length of its latus rectum is ______.

विकल्प

  • `2/3`

  • `4/3`

  • `1/3`

  • 4

MCQ
रिक्त स्थान भरें

उत्तर

If the parabola y2 = 4ax passes through the point (3, 2), then the length of its latus rectum is `4/3`.

Explanation:

Given parabola is y2 = 4ax

If the parabola is passing through (3, 2)

Then `(2)^2 = 4a xx 3`

⇒ `4 = 12a`

⇒ `a = 1/3`

Now length of the latus rectum = `4a = 4 xx 1/3 = 4/3`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Conic Sections - Exercise [पृष्ठ २०६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 11 Conic Sections
Exercise | Q 52 | पृष्ठ २०६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum.

y2 = 12x


Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum.

x2 = – 16y


Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum.

x2 = –9y


Find the area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of its latus rectum.


Find the area of the triangle formed by the lines joining the vertex of the parabola \[x^2 = 12y\]  to the ends of its latus rectum.


Find the coordinates of the point of intersection of the axis and the directrix of the parabola whose focus is (3, 3) and directrix is 3x − 4y = 2. Find also the length of the latus-rectum. 


(vii)  find the equation of the hyperbola satisfying the given condition:

foci (± 4, 0), the latus-rectum = 12


If the parabola y2 = 4ax passes through the point (3, 2), then find the length of its latus rectum. 


The vertex of the parabola (y + a)2 = 8a (x − a) is 


If the focus of a parabola is (−2, 1) and the directrix has the equation x + y = 3, then its vertex is 


The length of the latus-rectum of the parabola y2 + 8x − 2y + 17 = 0 is 


The vertex of the parabola x2 + 8x + 12y + 4 = 0 is


The length of the latus-rectum of the parabola 4y2 + 2x − 20y + 17 = 0 is 


The length of the latus-rectum of the parabola x2 − 4x − 8y + 12 = 0 is 


The focus of the parabola y = 2x2 + x is 


Which of the following points lie on the parabola x2 = 4ay


If the equation of the parabola is x2 = – 8y, find coordinates of the focus, the equation of the directrix and length of latus rectum.


The area of the triangle formed by the lines joining the vertex of the parabola x2 = 12y to the ends of its latus rectum is ______.


If the eccentricity of an ellipse is `5/8` and the distance between its foci is 10, then find latus rectum of the ellipse.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×