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प्रश्न
If the quotient obtained on dividing 3x3 + 11x2 + 34x + 106 by x – 3 is 3x2 + ax + b, then find a, b and also the remainder
उत्तर
p(x) = 3x3 + 11x2 + 34x + 106
d(x) = x – 3
x – 3 = 0
x = 3
The quotient is 3x2 + 20x + 94
The given quotient is 3x2 + ax + b
Compared with the given quotient
The value of a = 20 and b = 94
The remainder = 388
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