Question

The question is based on a set of conditions. Choose the response that most accurately and completely answer the question.

A science student has exactly four flasks - 1, 2, 3 and 4 - originally containing a red, a blue, a green, and an orange chemical, respectively. An experiment consists of mixing exactly two of these chemicals together by completely emptying the contents of one of the flasks into another of the flasks. The following conditions apply: The product of an experiment cannot be used in further experiments. Mixing the contents of 1 and 2 produces a red chemical. Mixing the contents of 2 and 3 produces an orange chemical. Mixing the contents of 3 with the contents of either 1 or 4 produces a blue chemical. Mixing the contents of 4 with the contents of either 1 or 2 produces a green chemical.

If the student performs exactly one experiment and exactly one of the resulting three non-empty flasks contains a blue chemical, which one of the following must be the colours of the chemicals in other two flasks?

विकल्प

• both green

• both orange

• both red

• one green and one red

Answer 1

both green

Explanation:

On the basis of given information, the arrangement  is as follows:   
No mix: 1 2 3 4  
Red (R) Blue (B) Green (G) Orange (O)   
Then, the rules they give in order...plus what is left in the other flasks... ‘–’ is the empty flask.   
→ Mixing 1 and 2 produces Red   
R – G O (2 into 1)  
– R G O (1 into 2)   
→ Mixing 2 and 3 produces Orange 
R – O O (2 into 3)   
R O – O (3 into 2)   
→ Mixing 3 with either 1 or 4 produces Blue   
B B – O (3 into 1)   
R B – B (3 into 4)   
→ Mixing 4 with either 1 or 2 produces Green   
G B G – (4 into 1)   
R G G – (4 into 2)   
Simplifying the outcomes:   
(R, G, O) (R, O, O) (B, B, O) (R, B, B) (G, B, G) And (R, G, G)

If the student performs exactly one experiment and  exactly one of the resulting three non-empty flasks  contains a blue chemical, then both green must be  the colour of the chemicals in other two flasks.