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प्रश्न
If the tension in the stretched string is increased by 69%, its fundamental frequency ______.
विकल्प
decreases by 30%
increases by 30%
increases by 69%
increases by 23%
MCQ
रिक्त स्थान भरें
उत्तर
If the tension in the stretched string is increased by 69%, its fundamental frequency increases by 30%.
Explanation:
∵ T2 = T1 + 69% of T1 = 1.69 T1
⇒ `T_2/T_1 = 1.69 = 169/100`
The fundamental frequency of a stretched string,
`f = 1/(2pi)sqrt(T/l)`
= `f ∝ sqrtT ⇒ f_2/f_1 = sqrt(T_2/T_1) = sqrt(169/100) = 13/10`
∵ % increase in frequency = `(f_2 - f_1)/f_1 xx 100`
= `(f_2/f_1 - 1) xx 100 = (13/10 - 1) xx 100`
= 30%
So, frequency increases by 30%.
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