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प्रश्न
If van't Hoff factor of monofluoroacetic acid in water is 1.076. What is it's degree of dissociation?
विकल्प
0.924
0.76
0.538
0.076
MCQ
उत्तर
0.076
Explanation:
i = 1.076
α = ?
\[\ce{CH2FCOOH ⇌ CH2FCOO^- + H^+}\]
∴ n = 2
α = `("i" - 1)/("n" - 1) = (1.076 -1)/(2 - 1)` = 0.076
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Colligative Properties of Electrolytes
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