Question

If x + y = `"t" + 1/"t"` and x² + y² = `"t"^2 + 1/"t"^2` then `150|x^2("dy")/("d"x)|` is ______.

विकल्प

• 120.00

• 130.00

• 140.00

• 150.00

Answer 1

If x + y = `"t" + 1/"t"` and x² + y² = `"t"^2 + 1/"t"^2` then `150|x^2("dy")/("d"x)|` is 150.00.

Explanation:

x² + y² = `("t" + 1/"t")^2 - 2`

x² + y² = (x + y)² – 2

xy = 1

⇒ `1/x`

⇒ `("dy")/("d"x) = - 1/x^2`

Now, `150|x^2 xx ("dy")/("d"x)|`

= `150|x^2 xx (-1/x^2)|`

= 150