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If y = cos3 (sec2 2t), find dydt - Mathematics

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प्रश्न

If y = cos3 (sec2 2t), find `dy/dt`

योग

उत्तर

y = cos3 (sec2 2t)

Applying chair Rule.

`dy/dt = 3 cos^2 (sec^2 2t) xx [(-sin (sec^2 2t)]xx2sec 2txxsec2t  x tan  2t xx2`

= − 12 cos2 (sec2 2t) × (sec2 2t) × sin(sec2 2t) × tan2t

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