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प्रश्न
In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.
उत्तर
Let ‘O’ be the centre of the circle and AB be the chord of the circle.
Here, d = 40 cm
∴ r = `40/2` = 20cm
Since OA = OB = AB,
ΔOAB is an equilateral triangle.
∴ The angle subtended at the centre by the minor
arc AOB is θ = 60° = `(60 xx pi/180)^"c"`
= `(pi/3)^"c"`
∴ `l` (minor arc of chord AB) = rθ
= `20 xx pi/3`
= `(20pi)/3" cm"`
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