Advertisements
Advertisements
प्रश्न
In both β− and β+ decay processes, the mass number of a nucleus remains the same, whereas the atomic number Z increases by one in β− decay and decreases by one in β+ decay. Explain giving reason.
उत्तर
In β− decay, a β particle of zero mass and −1 charge is emitted. The decay process is shown below:
Similarly, for a β+ decay, a β particle of negligibly small and +1 charge is emitted. The decay process is shown below:
संबंधित प्रश्न
An electron jumps from fourth to first orbit in an atom. How many maximum number of spectral lines can be emitted by the atom? To which series these lines correspond?
If wavelength for a wave is `lambda = 6000 Å,` then wave number will be ____________.
Which of the following transition will have highest emission frequency?
In hydrogen atom, the product of the angular momentum and the linear momentum of the electron is proportional to (n = principal quantum number) ____________.
Continuous spectrum is produced by ______.
The first four spectral lines in the Lyman series of a H-atom are λ = 1218 Å, 1028Å, 974.3 Å and 951.4 Å. If instead of Hydrogen, we consider Deuterium, calculate the shift in the wavelength of these lines.
The frequencies for series limit of Balmer and Paschen series respectively are 'v1' and 'v3'. If frequency of first line of Balmer series is 'v2' then the relation between 'v1', 'v2' and 'v3' is ______.
In the hydrogen atoms, the transition from the state n = 6 to n = 1 results in ultraviolet radiation. Infrared radiation will be obtained in the transition.
The frequency of the series limit of the Balmer series of the hydrogen atoms of Rydberg’s constant R and velocity of light c is ______.
Calculate the wavelength of the first two lines in the Balmer series of hydrogen atoms.