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In comparison to a 0.01 m solution of glucose, the depression in freezing point of a 0.01 m MgCl2 solution is ______. - Chemistry

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प्रश्न

In comparison to a 0.01 m solution of glucose, the depression in freezing point of a 0.01 m MgCl2 solution is ______.

विकल्प

  • the same

  • about twice

  • about three times

  • about six times

MCQ
रिक्त स्थान भरें

उत्तर

In comparison to a 0.01 m solution of glucose, the depression in freezing point of a 0.01 m MgCl2 solution is about three times.

Explanation:

0.01 m solution of glucose does not ionize while 0.01 m  MgCl2 solution furnishes 3 ions \[\ce{(Mg^{2+} + 2Cl^-)}\] in the solution, hence the value of colligative property for  MgCl2 solution is about 3 times.

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अध्याय 2: Solutions - Exercises [पृष्ठ १९]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 2 Solutions
Exercises | Q I. 11. | पृष्ठ १९

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(C) 0.5 M A12(SO4)3

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Read the passage carefully and answer the questions that follow:

Henna is investigating the melting point of different salt solutions.
She makes a salt solution using 10 mL of water with a known mass of NaCl salt.
She puts the salt solution into a freezer and leaves it to freeze.
She takes the frozen salt solution out of the freezer and measures the temperature when the frozen salt solution melts.
She repeats each experiment.

 

S.No Mass of the salt
used in g
Melting point in °C
Readings Set 1 Reading Set 2
1 0.3 -1.9 -1.9
2 0.4 -2.5 -2.6
3 0.5 -3.0 -5.5
4 0.6 -3.8 -3.8
5 0.8 -5.1 -5.0
6 1.0 -6.4 -6.3

Assuming the melting point of pure water as 0°C, answer the following questions:

  1. One temperature in the second set of results does not fit the pattern. Which temperature is that? Justify your answer.
  2. Why did Henna collect two sets of results?
  3. In place of NaCl, if Henna had used glucose, what would have been the melting point of the solution with 0.6 g glucose in it?
    OR
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  1. 0.10 M Ba3 (PO4)2
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  3. 0.10 M KCl
  4. 0.10 M Li3 PO

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