Advertisements
Advertisements
प्रश्न
In the first proof reading of a book containing 300 pages the following distribution of misprints was obtained:
No. of misprints per page (x) | 0 | 1 | 2 | 3 | 4 | 5 |
No. of pages (f) | 154 | 95 | 36 | 9 | 5 | 1 |
Find the average number of misprints per page.
उत्तर
Let the assumed mean (A) = 2
No. of misprints per page (x1) | No. of pages(f1) |
u1 = x1 - A = x1 - 2 |
f1u1 |
0 | 154 | -2 | -308 |
1 | 95 | -1 | -95 |
2 | 36 | 0 | 0 |
3 | 9 | 1 | 9 |
4 | 5 | 2 | 10 |
5 | 1 | 3 | 3 |
N = 300 | `sumf_1"u"_1=381` |
Average number of mis prints per day `=A+(sumf_1"u"_1)/N`
`=2+(-381)/300`
`=2-381/300`
`=(600-381)/300`
`=219/300`
= 0.73
APPEARS IN
संबंधित प्रश्न
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.
Number of plants | 0 - 2 | 2 - 4 | 4 - 6 | 6 - 8 | 8 - 10 | 10 - 12 | 12 - 14 |
Number of houses | 1 | 2 | 1 | 5 | 6 | 2 | 3 |
Which method did you use for finding the mean, and why?
The following distribution shows the daily pocket allowance of children of a locality. If the mean pocket allowance is ₹ 18 , find the missing frequency f.
Daily pocket allowance (in Rs.) |
11-13 | 13-15 | 15-17 | 17-19 | 19-21 | 21-23 | 23-25 |
Number of children | 7 | 6 | 9 | 13 | f | 5 | 4 |
The mean of the following frequency data is 42, Find the missing frequencies x and y if the sum of frequencies is 100
Class interval |
0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 |
Frequency | 7 | 10 | x | 13 | y | 10 | 14 | 9 |
Find x and y.
Find the mean of the following frequency distribution using step-deviation method
Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
Frequency | 7 | 10 | 15 | 8 | 10 |
If the mean of the following frequency distribution is 18, find the missing frequency.
Class interval | 11 – 13 | 13 – 15 | 15 – 17 | 17 – 19 | 19 – 21 | 21 – 23 | 23 – 25 |
Frequency | 3 | 6 | 9 | 13 | f | 5 | 4 |
The mean of first n odd natural numbers is \[\frac{n^2}{81}\],then n =
In the formula
The following frequency distribution table shows the amount of aid given to 50 flood affected families. Find the mean of the amount of aid.
Amount of aid
(Thousand rupees)
|
50 - 60 | 60 - 70 | 70 - 80 | 80 - 90 | 90 - 100 |
No. of families | 7 | 13 | 20 | 6 | 4 |
A car travels from city A to city B, 120 km apart at an average speed of 50km/h. It then makes a return trip at an average speed of 60km/h. It covers another 120km distance at an average speed of 40km/h. The average speed over the entire 360km will be ______.
The distribution given below shows the runs scored by batsmen in one-day cricket matches. Find the mean number of runs.
Runs scored |
0 – 40 | 40 – 80 | 80 – 120 | 120 – 160 | 160 – 200 |
Number of batsmen |
12 | 20 | 35 | 30 | 23 |