Question

In Freundlich's adsorption isotherm, when log `("x"/"m")` is plotted against log P, slope of the graph is ____________.

विकल्प

• k

• `1/"k"`

• n

• `1/"n"`

Answer 1

In Freundlich's adsorption isotherm, when log `("x"/"m")` is plotted against log P, slope of the graph is `underline(1/"n")`.

Explanation:

Frendlich's adsorption isotherm,

`"x"/"m"` = k P^1/n

`log  "x"/"m" = log "k" + 1/"n" log "P"`

`log  "x"/"m" = 1/"n" log "P" + log "k"`

Compare with y = mx + c

Slope m = `1/"n"`