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In a Game of Chance, a Spinning Arrow Comes to Rest at One of the Numbers 1, 2, 3, 4, 5, 6, 7, 8. All These Are Equally Likely Outcomes. Find the Probability that It Will Rest at A Number Less T - Algebra

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प्रश्न

In a game of chance, a spinning arrow comes to rest at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8. All these are equally likely outcomes. Find the probability that it will rest at  a number less than 9.

उत्तर

Total number of outcomes  = 8

Number of favourable outcomes (a number less than 9) = 1, 2, 3, 4, 5, 6, 7, 8
= 8 

Therefore, required probability =`\text {Number of favorable outcomes}/text { Total number of outcomes}`

`=8/8`

  =1

Hence, the probability that the spinning arrow will rest at a number less than 9 is 1.

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अध्याय 5: Probability - Problem Set 5 [पृष्ठ १२७]

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बालभारती Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board
अध्याय 5 Probability
Problem Set 5 | Q 10.4 | पृष्ठ १२७

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