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प्रश्न
In a hot water heating system, there is a cylindrical pipe of length 28 m and diameter 5 cm. Find the total radiating surface in the system.
`["Assume "pi=22/7]`
उत्तर
Height (h) of cylindrical pipe = Length of cylindrical pipe = 28 m
Radius (r) of circular end of pipe = (5/2) = 2.5 cm = 0.025 m
CSA of cylindrical pipe = 2πrh
`=(2xx22/7xx0.025xx28)m^2`
= 4.4m2
The area of the radiating surface of the system is 4.4 m2.
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