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In system of two particles of masses 'm1' and 'm2', the first particle is moved by a distance 'd' towards the centre of mass. To keep the centre of mass unchanged, the second particle will have -

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प्रश्न

In system of two particles of masses 'm1' and 'm2', the first particle is moved by a distance 'd' towards the centre of mass. To keep the centre of mass unchanged, the second particle will have to be moved by a distance ______.

विकल्प

  • `"m"_2/"m"_1 "d"`, towards the centre of mass

  • `"m"_1/"m"_2 "d"`, away from the centre of mass

  • `"m"_1/"m"_2 "d"`, towards the centre of mass

  • `"m"_2/"m"_1 "d"`, away from the centre of mass

MCQ
रिक्त स्थान भरें

उत्तर

In system of two particles of masses 'm1' and 'm2', the first particle is moved by a distance 'd' towards the centre of mass. To keep the centre of mass unchanged, the second particle will have to be moved by a distance `underline("m"_1/"m"_2 "d"," towards the centre of mass")`.

Explanation:

Let x1 and x2 be the position of masses m, and m2, respectively.

The position of centre of mass is

`"x"_"CM" = ("x"_1"m"_1 + "x"_2"m"_2)/("m"_1 + "m"_2)`

If Δ x1 and Δ x2 be the changes in positions, then change in the position of centre of mass,

`Δ "x"_"CM" = (Δ"x"_1"m"_1 + Δ"x"_2"m"_2)/("m"_1 + "m"_2)`

Given that, the centre of mass remains unchanged i.e., Δ XCM = 0 and Δ x1 = d.

`=> 0 = ("dm"_1 + "m"_2 Delta x_2)/("m"_1 + "m"_2)`

or `Delta x_2 = - "m"_1/"m"_2`d

Here, negative sign shows that the second particle should be moved towards the centre of mass.

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