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प्रश्न
In the figure below ‘A’ shows a cell in the normal state and ‘B’ shows the same cell after leaving it in a certain solution for a few minutes.
(i) Describe the change which has occurred in the cell as seen in B.
(ii) Give the technical term for the condition of the cell as reached in B and as it was in A.
(iii) Define the process which led to this condition.
(iv) What was the solution-isotonic, hypotonic or hypertonic, in which the cell was kept?
(v) How can the cell in B, be brought back to its original condition?
(vi) Name the parts numbered 1 to 3.
उत्तर
(i) Exosmosis (exit of water) has resulted in the shrinkage of the protoplasm of cell B.
(ii) Plasmolysis and deplasmolysis.
(iii) When plant cells are kept in a hypertonic solution, exosmosis takes place. This process is called plasmolysis.
(iv) Hypertonic solution.
(v) The cell in B can be brought back to its original condition by placing it in a drop of distilled water.
(vi) 1. Cell wall, 2. Plasma membrane, 3. Chloroplast.
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संबंधित प्रश्न
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(i) What can you say about the size of the holes in the membrane, if it is to behave semi- permeably between these two?
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Give Technical Term for the following.
The pressure which is responsible for the movement of water molecules across the cortical cells of the root.
Mention, if the following statement is True or False. If false rewrite the wrong statement in its correct form:
During exosmosis, water moves from inside the cell to the outside of the cell.
Define the following term:
Tonicity
