Question

In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is ______.

विकल्प

• 5

• 2

• 0.5

• 0.2

Answer 1

In vertical circular motion, the ratio of kinetic energy of a particle at highest point to that at lowest point is 0.2.

Explanation:

We know in vertical circle velocity of a particle at lowest point, v_l = `sqrt(5"gr")`

velocity of particle at highest point, v_h = `sqrt"rg"`

So, KE at highest point of the vertical circle

K_h = `1/2`m rg = `"mgr"/2`

and KE at lowest point of the vertical circle

(K_l) = `1/2`m 5gr = `(5"mgr")/2`

So, required ratio `"K"_"h"/"K"_"t"=("mgr"/2)/((5"mgr")/2)`

= `1/5` = 0.2