Question

In Young's double slit experiment the two slits are 0.6 mm distance apart. Interference pattern is observed on a screen at a distance 80 cm from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be ______ nm.

विकल्प

• 150

• 250

• 350

• 450

Answer 1

In Young's double slit experiment the two slits are 0.6 mm distance apart. Interference pattern is observed on a screen at a distance 80 cm from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be 450 nm.

Explanation:

Given, `"d"/2` = position of Ist dark range

⇒ `"d"/2=beta/2`

⇒ d = `(lambda"D")/"d"`

⇒ λ = `"d"^2/"D" = (0.6xx10^-3)^2/0.8`

= 450 × 10^-9 m