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प्रश्न
Integrate the following with respect to x:
`1/3 cos(x/3 - 4) + 7/(7x + 9) + "e"^(x/5 + 3)`
उत्तर
= `int[1/3 cos(x/3 - 4) + 7/(7x + 9) + "e"^(x/5 + 3)] "d"x`
= `1/3 int cos(x/3 - 4) "d"x + 7 int 1/(7x + 9) "d"x + int"e"^(x/5 + 3) "d"x`
= `1/3 (sin(x/3 - 4))/(1/3) + (7log|7x + 9|)/7 + ("e"^(x/5 + 3))/(1/5) + "c"`
= `sin(x/3 - 4) + log|7x + 9| + 5"e"^(x/5 + 3) + "c"`
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