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प्रश्न
Integrate the following with respect to x.
`("e"^(3x) - "e"^(-3x))/"e"^x`
उत्तर
`int (("e"^(3x) - "e"^(-3x))/"e"^x) "d"x = int ("e"^(3x)/"e"^x - "e"^(-3x)/"e"^x) "d"x`
= `int ("e"^(2x) - "e"^(-4x)) "d"x`
= `"e"^(2x)/2 - "e"^(-4x)/(-4) + "c"`
= `"e"^(2x)/2 + "e"^(-4x)/4 + "c"`
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