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प्रश्न
Ionisation constant of a weak base MOH, is given by the expression
`K_b = ([M^+][OH^-])/([MOH])`
Values of ionisation constant of some weak bases at a particular temperature are given below:
| Base | Dimethylamine | Urea | Pyridine | Ammonia |
| \[\ce{K_b}\] | 5.4 × 10–4 | 1.3 × 10–14 | 1.77 × 10–9 | 1.77 × 10–5 |
Arrange the bases in decreasing order of the extent of their ionisation at equilibrium. Which of the above base is the strongest?
उत्तर
Higher the value of \[\ce{K_b}\] stronger will be the base.
Kb- 5.4 × 10–4 > 1.77 × 10–5 > 1.77 × 10–9 > 1.3 × 10–14
Decreasing order of basic strength.
Dimethylamine > Ammonia > Pyridine > Urea
Hence among the given bases, the strongest base is Dimethylamine.
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