Advertisements
Advertisements
प्रश्न
Is it possible to have a polygon, whose sum of interior angle is: 7 right-angles
उत्तर
Let no. of sides = n
Sum of angles = 7 right angles = 7 x 90 = 630°
(n – 2) x 180° = 630°
n – 2 = `630/180`
n – 2 = `7/2`
n = `7/2` + 2
n = `11/2`
Which is not a whole number. Hence it is not possible to have a polygon, the sum of whose interior angles is 7 right-angles.
APPEARS IN
संबंधित प्रश्न
Calculate the sum of angle of a polygon with: 10 sides
Calculate the sum of angle of a polygon with: 20 sides
Calculate the sum of angle of a polygon with : 25 sides
Find the number of sides in a polygon if the sum of its interior angle is: 1620°
The interior angles of a pentagon are in the ratio 4 : 5 : 6 : 7 : 5. Find each angle of the pentagon.
Two angles of a hexagon are 120° and 160°. If the remaining four angles are equal, find each equal angle.
Two angles of a polygon are right angles and the remaining are 120° each. Find the number of sides in it.
In a hexagon ABCDEF, side AB is parallel to side FE and ∠B : ∠C : ∠D : ∠E = 6 : 4 : 2 : 3. Find ∠B and ∠D.
The angles of a hexagon are x + 10°, 2x + 20°, 2x – 20°, 3x – 50°, x + 40° and x + 20°. Find x.
In a pentagon, two angles are 40° and 60°, and the rest are in the ratio 1 : 3 : 7. Find the biggest angle of the pentagon.
