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Justify that the following reaction is redox reaction: 4NHX3(g)+5OX2(g)⟶4NO(g)+6HX2O(g) - Chemistry

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प्रश्न

Justify that the following reaction is redox reaction:

\[\ce{4 NH3(g) + 5 O2(g) → 4NO(g) + 6H2O(g)}\]

संख्यात्मक

उत्तर

The oxidation number of each element in the given reaction can be represented as:
 -3 +1              0                  +2 -2           +1  -2
\[\ce{4 NH3(g) + 5 O2(g) → 4NO(g) + 6H2O(g)}\]

Here, the oxidation number of N increases from - 3 in NH3 to +2 in NO. On the other hand, the oxidation number of O2 decreases from 0 in O2 to - 2 in NO and H2O i.e., O2 is reduced. Hence, the given reaction is a redox reaction.

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Oxidation Number - Types of Redox Reactions
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अध्याय 8: Redox Reactions - EXERCISES [पृष्ठ २८०]

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एनसीईआरटी Chemistry - Part 1 and 2 [English] Class 11
अध्याय 8 Redox Reactions
EXERCISES | Q 8.3 - (e) | पृष्ठ २८०

संबंधित प्रश्न

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\[\ce{CuO(s) + H2(g) → Cu(s) + H2O(g)}\]


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\[\ce{2AgBr (s) + C6H6O2(aq) → 2Ag(s) + 2HBr (aq) + C6H4O2(aq)}\]


Identify the substance oxidised, reduced, oxidising agent and reducing agent for the following reaction:

\[\ce{HCHO(l) + 2[Ag (NH3)2]+(aq) + 3OH–(aq) → 2Ag(s) + HCOO–(aq) + 4NH3(aq) + 2H2O(l)}\]


Identify the substance oxidised, reduced, oxidising agent and reducing agent for the following reaction:

\[\ce{HCHO (l) + 2Cu^{2+}(aq) + 5 OH–(aq) → Cu2O(s) + HCOO–(aq) + 3H2O(l)}\]


What sorts of informations can you draw from the following reaction ?

\[\ce{{(CN)}_{2(g)} + 2OH-_{(aq)} -> CN-_{(aq)} + CNO-_{(aq)} + H_2O_{(l)}}\]


Refer to the periodic table given in your book and now answer the following questions:

Select the possible non-metals that can show disproportionation reaction.


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Al, Cu, Fe, Mg and Zn.


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\[\ce{Cu + Zn^{2+} ->Cu^{2+} + Zn}\]


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\[\ce{2KClO3 → 2KCl +3O2}\]


Which of the following examples does not represent disproportionation?


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\[\ce{S8(s) + {a} OH^-(aq) -> {b} S^{2-}(aq) + {c} S2O^{2-}3(aq) + {d} H2O(l)}\]

The values of 'a' are ______. (Integer answer)


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\[\ce{H2O + O -> H2O2}\]

[Given: Na (Avogadro's No.) = 6 × 1023]


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