Advertisements
Advertisements
प्रश्न
Let A = {–1, 1} and B = {0, 2}. If the function f: A → B defined by f(x) = ax + b is an onto function? Find a and b
उत्तर
A = {–1, 1}; B = {0, 2}
f(x) = ax + b
f(–1) = a(–1) + b
0 = –a + b
a – b = 0 ….(1)
f(1) = a(1) + b
2 = a + b
a + b = 2 ….(2)
Solving (1) and (2) we get
a – b = 0 ....(1)
a + b = 2 ....(2)
(1) + (2) ⇒ 2a = 2
a = `(2)/(2)` = 1
Substitute a = 1 in (1)
The value of a = 1 and b = 1
APPEARS IN
संबंधित प्रश्न
Show that the function f : N → N defined by f(x) = 2x – 1 is one-one but not onto
Show that the function f : N → N defined by f(m) = m2 + m + 3 is one-one function
In the following case state whether the function is bijective or not. Justify your answer
f: R → R defined by f(x) = 2x + 1
In the following case state whether the function is bijective or not. Justify your answer
f: R → R defined by f(x) = 3 – 4x2
The distance S object travel under the influence of gravity in time t seconds is given by S(t) = `1/2` gt2 + at + b where, (g is the acceleration due to gravity), a, b are constant. Verify whether the function S(t) is one-one or not.
Multiple choice question :
Let A = {1, 2, 3, 4} and B = {4, 8, 9, 10}. A function f: A → B given by f = {(1, 4), (2, 8), (3, 9), (4, 10)} is a
Multiple choice question :
If f : A → B is a bijective function and if n(B) = 7, then n(A) is equal to
Let A = {1, 2, 3, 4} and B = N. Let f : A → B be defined by f(x) = x3 then, identify the type of function