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प्रश्न
Let α and β be the roots of the equation, 5x2 + 6x – 2 = 0. If Sn = αn + βn, n = 1, 2, 3, ....., then ______.
विकल्प
5S6 + 6S5 + 2S4 = 0
6S6 + 5S5 = 2S4
6S6 + 5S5 + 2S4 = 0
5S6 + 6S5 = 2S4
MCQ
रिक्त स्थान भरें
उत्तर
Let α and β be the roots of the equation, 5x2 + 6x – 2 = 0. If Sn = αn + βn, n = 1, 2, 3, ....., then `underlinebb(5S_6 + 6S_5 = 2S_4)`.
Explanation:
5x2 + 6x – 2 = 0
α + β = `(-6)/5`
αβ = `(-2)/5`
and 5x2 + 6x – 2 = 0
⇒ 5α2 = –6α + 2
Similarly, 5β2 = –6β + 2
= αn + βn
S6 = α6 + β6
S5 = α5 + β5
S4 = α4 + β4
6S5 – 2S4 = 6(α5 + β5) – 2(α4 + β4)
= α4(6α – 2) + β4(6β – 2)
= α4(–5α2) + β4(–5β2)
= –5(α6 + β6)
= –5S6
⇒ 5S6 + 6S5 = 2S4
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