Advertisements
Advertisements
प्रश्न
Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is
विकल्प
19
21
23
25
उत्तर
23
Explanation:
L.C.M. of 15, 20 and 28
= 2 × 2 × 5 × 3 × 7
= 420
Greatest 4 digit number = 9999.
The greatest 4 digit number is divisible by 420 = 9660.
The remainder in each case = 2.
Required number = 9660 + 2 = 9662.
Sum of digits = 9 + 6 + 6 + 2 = 23.
APPEARS IN
संबंधित प्रश्न
By how much is `3/4` of 968 less than `7/8` of 1008?
x ex dx is equal to:
d (sec-1x) is equal to:
Which one is rational number ?
In algebric fractions, numerators and denominators are
6 × 3 (3 –1) is equal to
If (9/7)3× (49/81)2x-6= (7/9)9, then the value of x is:
The least value of x, for which the expression x2+ x + 17 will not give a prime number, is
The sum of the two numbers is 2490. If 6.5% of one number is equal to 8.5% of the other, the numbers are
Which of the following numbers should be added to 11158 to make it exactly divisible by 77?
