Question

मान ज्ञात कीजिए।

` [tan 60°]/ [ sin 60° + cos 60°]`

Answer 1

` [tan 60°]/ [ sin 60° + cos 60°]`

= `sqrt 3/{sqrt3/2 + 1/2}`

= `sqrt 3/[(sqrt 3 + 1)/2]`

= `sqrt3 xx 2/(sqrt3 + 1)`

= `(2 sqrt3)/(sqrt3 + 1)`

= `(2sqrt3(sqrt3-1))/((sqrt3+1)(sqrt3+1)`   

= `(2sqrt3(sqrt3-1))/((sqrt3)^2 - (1)^2) ...[∵ (a + b) (a - b) = a^2 - b^2]`

= `(2sqrt3(sqrt3-1))/(3-1)`

= `(2sqrt3(sqrt3-1))/(2)`

= `sqrt3(sqrt3-1)`