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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा ८

Match the following : Column A Column B (a) x2 = 10 (i) x = 4 (b) 20 = 6x − 4 (ii) x = 1 (c) 2x − 5 = 3 − x (iii) x = 20 (d) 7x −4 −8x = 20 (iv) x = 83 (e) 411-x=-711 (v) x = −24 - Mathematics

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प्रश्न

Match the following :

Column A Column B
(a) `x/2` = 10 (i) x = 4
(b) 20 = 6x − 4 (ii) x = 1
(c) 2x − 5 = 3 − x (iii) x = 20
(d) 7x − 4 − 8x = 20 (iv) x = `8/3`
(e) `4/11 - x = (-7)/11` (v) x = −24

विकल्प

  • (i), (ii), (iv), (iii), (v)

  • (iii), (iv), (i), (ii), (v)

  • (iii), (i), (iv), (v), (ii)

  • (iii), (i), (v), (iv), (ii)

MCQ
जोड़ियाँ मिलाइएँ

उत्तर

(iii), (i), (iv), (v), (ii)

Explanation; 

Hint:

(a) `x/2` = 10, multiplying by 2 on both sides, we get

`x/2 xx 2` = 10 × 2

⇒ x = 20

(b) 20 = 6x – 4 by transposition ⇒ 20 + 4 = 6x

6x = 24 dividing by 6 on both sides,

`(6x)/6 = 24/6`

⇒ x = 4

(c) 2x – 5 = 3 – x

By transposing the variable ‘x’, we get

2x – 5 + x = 3

by transposing – 5 to other side,

2x + x = 3 + 5

∴ 3x = `8, (3x)/3 = 8/3`

∴ x = `8/3`

(d) 7x – 4 – 8x = 20

by transposing – 4 to other side,

7x – 8x = 20 + 4

– x = 24

∴ x = – 24

(e) `4/11 - x = (-7)/11`

Transposing `4/11` to other side,

– x = `(-7)/11 (-4)/11`

= `(-7 - 4)/11`

= `(-11)/11`

= – 1

∴ – x = – 1

⇒ x = 1

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अध्याय 3: Algebra - Exercise 3.6 [पृष्ठ १०२]

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सामाचीर कलवी Mathematics [English] Class 8 TN Board
अध्याय 3 Algebra
Exercise 3.6 | Q 3 | पृष्ठ १०२
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