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प्रश्न
Match the statements given in Column I with the oxidation states given in Column II.
| Column I | Column II | |
| (i) | Oxidation state of Mn in MnO2 is | (a) + 2 |
| (ii) | Most stable oxidation state of Mn is | (b) + 3 |
| (iii) | Most stable oxidation state of | (c) + 4 |
| Mn in oxides is | (d) + 5 | |
| (iv) | Characteristic oxidation state of lanthanoids is | (e) + 7 |
उत्तर
| Column I | Column II | |
| (i) | Oxidation state of Mn in MnO2 is | (c) + 4 |
| (ii) | Most stable oxidation state of Mn is | (a) + 2 |
| (iii) | Most stable oxidation state of Mn in oxides is | (e) + 7 |
| (iv) | Characteristic oxidation state of lanthanoids is | (b) + 3 |
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संबंधित प्रश्न
Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state.
Compare the chemistry of actinoids with that of the lanthanoids with special reference to oxidation state.
What are the consequences of lanthanoid contraction?
Explain the cause of Lanthanoids contraction.
What is Lanthanoid contraction?
General electronic configuration of actinoids is `(n-2)f^(1-14)(n - 1)d^(0-2)ns^2`.Which of the following actinoids have one electron in 6d orbital?
(i) U (Atomic no. 92)
(ii) Np (Atomic no.93)
(iii) Pu (Atomic no. 94)
(iv) Am (Atomic no. 95)
How would you account for the following:
There is a greater range of oxidation states among the actinoids than among the lanthanides.
The titanium (Z = 22) compound that does not exist is:-
In lanthanoid the last electron enters (n - 2)f subshell where n is equal to ______.
Which one of the lanthanoids given below is the most stable in divalent form?
