हिंदी

Measure of two quantities along with the precision of respective measuring instrument is A = 2.5 ms–1 ± 0.5 ms–1 B = 0.10 s ± 0.01 s. The value of A B will be ______. - Physics

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प्रश्न

Measure of two quantities along with the precision of respective measuring instrument is A = 2.5 ms–1 ± 0.5 ms–1 B = 0.10 s ± 0.01 s. The value of A B will be ______.

विकल्प

  • (0.25 ± 0.08) m

  • (0.25 ± 0.5) m

  • (0.25 ± 0.05) m

  • (0.25 ± 0.135) m

MCQ
रिक्त स्थान भरें

उत्तर

Measure of two quantities along with the precision of respective measuring instrument is A = 2.5 ms–1 ± 0.5 ms–1 B = 0.10 s ± 0.01 s. The value of A B will be (0.25 ± 0.08) m.

Explanation:

The resultant significant figure in multiplication and addition is equal to the minimal number of significant figures.

A = (2.5 ± 0.5) ms–1

B = (0.10 ± 0.01) s

X = AB = 2.5 × 0.10

= 0.25 m

`(Δx)/x = (ΔA)/A + (ΔB)/B`

`(Δx)/x = 0.5/2.5 + 0.01/0.10`

`(Δx)/x = 0.075/0.25`,

`Δx` = 0.007

≅ 0.08

∴ AB = (2.5 ± 0.08) m

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Errors in Measurements
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अध्याय 2: Units and Measurements - Exercises [पृष्ठ ६]

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एनसीईआरटी एक्झांप्लर Physics [English] Class 11
अध्याय 2 Units and Measurements
Exercises | Q 2.7 | पृष्ठ ६
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