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प्रश्न
Mohan invested a certain sum at compound interest, compounded annually. If the interests for two successive years were Rs 600 and Rs 648, calculate the rate of interest and the sum invested.
उत्तर
For the second year:
A=Rs 648 ; P=Rs 600 ; n=1 ; r = ?
`therefore "A" = "P" (1 + "r"/100)^"n"`
`⇒ 648 = 600 (1 + "r"/100)^1`
⇒ 648 = 600 + 6r
⇒ 6r = 48
⇒ r = 8
Hence, rate of interest = 8 %
For the first year:
I=Rs 600 ; r=8 % ; n=1 ; P = ?
`"I" =("P" xx "r" xx "n")/100`
Rs 600 = Rs `("P" xx 8 xx 1)/100`
P = Rs `60000/8`
P = Rs 7,500
The sum invested= Rs 7,500.
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