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Molecular orbital electronic configuration for 'X' anion is- KK σ*2s2 σ*2s2 π2px2 π2py2 σ2pz2 π*2px1, the anion 'X' is. -

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प्रश्न

Molecular orbital electronic configuration for 'X' anion is- KK σ*2s2 σ*2s2 π2px2 π2py2 σ2pz2 π*2px1, the anion 'X' is.

विकल्प

  • \[\ce{N^{-}2}\]

  • \[\ce{O^{-}2}\]

  • \[\ce{N^{2-}2}\]

  • \[\ce{O^{2-}2}\]

MCQ

उत्तर

\[\ce{N^{-}2}\]

Explanation:

Given that anion X's electronic configuration is σ1s2 σ*1s2, σ2s2, π2px2 ≈ π2py2, σ2pz2, π*2px1

∴ Total amount of anion electrons X = 15

As a result, the anion X is \[\ce{N^{-}2}\]

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