हिंदी

Mr. Mehra sends his servant to the market to buy oranges worth Rs. 15. The servant having eaten three oranges on the way, Mr. Mehra pays Rs. 25 paise per orange more than the market price - Mathematics

Advertisements
Advertisements

प्रश्न

Mr. Mehra sends his servant to the market to buy oranges worth Rs. 15. The servant having eaten three oranges on the way, Mr. Mehra pays Rs. 25 paise per orange more than the market price. Taking x to be the number of oranges which Mr. Mehra receives, form a quadratic equation in x. Hence, find the value of x.

योग

उत्तर

Number of oranges = y

Cost of one orange = Rs. 15/y

The servant ate 3 oranges, so Mr. Mehra received (y – 3) oranges.

So, x = y – 3

`\implies` y = x + 3  ...(1)

Cost of one orange paid by Mr. Mehra = Rs. `15/y + 0.25`

= Rs. `15/(x + 3) + 1/4`  ...[Using (1)]

Now, Mr. Mehra pays a total of Rs. 15

∴ `(15/(x + 3) + 1/4) xx x = 15`

`(60 + x + 3)/(4(x + 3)) xx x = 15`

63x + x2 = 60x + 180

x2 + 3x – 180 = 0

(x + 15)(x – 12) = 0

x = –15, 12

But, the number of oranges cannot be negative.

So, x = 12.

shaalaa.com
Miscellaneous Problems
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (D) [पृष्ठ ७८]

APPEARS IN

सेलिना Mathematics [English] Class 10 ICSE
अध्याय 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (D) | Q 8 | पृष्ठ ७८

संबंधित प्रश्न

The sum S of n successive odd numbers starting from 3 is given by the relation: S = n(n + 2). Determine n, if the sum is 168.


One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages.


Rs. 250 is divided equally among a certain number of children. If there were 25 children more, each would have received 50 paise less. Find the number of children.


A trader bought a number of articles for Rs. 1,200. Ten were damaged and he sold each of the remaining articles at Rs. 2 more than what he paid for it, thus getting a profit of Rs. 60 on the whole transaction. Taking the number of articles he bought as x, form an equation in x and solve it.


Rs. 6500 was divided equally among a certain number of persons. Had there been 15 persons more, each would have got Rs. 30 less. Find the original number of persons.


In an auditorium, seats were arranged in rows and columns. The number of rows was equal to the number of seats in each row. When the number of rows was doubled and the number of seats in each row was reduced by 10, the total number of seats increased by 300. Find:

  1. the number of rows in the original arrangement.
  2. the number of seats in the auditorium after re-arrangement.

Mohan takes 16 days less than Manoj to do a piece of work. If both working together can do it in 15 days, in how many days will Mohan alone complete the work?


Two years ago, a man’s age was three times the square of his son’s age. In three years time, his age will be four times his son’s age. Find their present ages.


The ages of two sisters are 11 years and 14 years. In how many years’ time will the product of their ages be 304? 


₹ 320 were divided equally among 8 children. If 2 more children join them, each will get, how many rupees more or less?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×