हिंदी
सी.आई.एस.सी.ई.आईसीएसई ICSE Class 6

Multiply: 3abc and − 5a2b2c - Mathematics

Advertisements
Advertisements

प्रश्न

Multiply:

3abc and − 5a2b2c

योग

उत्तर

3abc × − 5a2b2c

= 3 × − 5 × a1+2 × b1+2 × c1+1

= − 15a3b3c2

shaalaa.com
Concept for Unknowns Through Examples with Simple Contexts (Single Operations)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Fundamental Operations (Related to Algebraic Expressions) - Exercise 19 (C)

APPEARS IN

सेलिना Mathematics [English] Class 6
अध्याय 19 Fundamental Operations (Related to Algebraic Expressions)
Exercise 19 (C) | Q 8.1
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×