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प्रश्न
Obtain the differential equation by eliminating arbitrary constants from the following equation.
y2 = (x + c)3
उत्तर
y2 = (x + c)3 ...(i)
Differentiating w.r.t. x, we get
`2y dy/dx = 3 (x+c)^2` ...(ii)
Dividing (i) by (ii), we get
`y^2/(2y(dy/dx)) = ((x+c)^3)/(3(x+c)^2)`
∴ `y/(2(dy/dx)) = (x+c)/3`
∴ `x+c = (3y)/(2(dy/dx))`
∴ `c=-x +(3y)/(2(dy/dx))`
Substituting the value of c in (i), we get
`y^2 = [x+(-x+(3y)/(2(dy/dx)))]^3`
= `((3y)/(2(dy/dx)))^3`
∴ `y^2 = (27y^3)/(8(dy/dx)^3`
∴ `(dy/dx)^3 = (27y)/8`
∴ `dy/dx = 3/2root3y`
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