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प्रश्न
On the same graph paper, plot the graphs of y = 2x - 1, y = 2x and y = 2x + 1 from x = - 2 to x = 4. Are the graphs (lines) drawn parallel to each other?
उत्तर
First, prepare a table as follows:
| X | -1 | 0 | 1 |
| Y = 2x - 1 | -3 | -1 | 1 |
| Y = 2x | -2 | 0 | 2 |
| Y = 2x + 1 | -1 | 1 | 3 |
Now the graph can be drawn as follows:
The lines are parallel to each other.
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संबंधित प्रश्न
Draw the graphs of the following equations on the same system of co-ordinates. Write the co-ordinates of their points of intersection.
x + 4 = 0, y - 1 = 0, 2x + 3 = 0, 3y - 15 = 0
Draw the graph for the linear equation given below:
y = 0
Draw the graph for the each linear equation given below:
y = `(3x)/(2) + (2)/(3)`
Draw the graph for the linear equation given below:
2x - 3y = 4
Draw the graph for the linear equation given below:
x + 5y + 2 = 0
Draw the graph for the equation given below:
`(1)/(2) x + (2)/(3) y = 5`.
For the linear equation, given above, draw the graph and then use the graph drawn (in the following case) to find the area of a triangle enclosed by the graph and the co-ordinates axes:
7 - 3 (1 - y) = -5 + 2x
On the same graph paper, plot the graph of y = x - 2, y = 2x + 1 and y = 4 from x= - 4 to 3.
Draw the graph of the equation 3x - 4y = 12.
Use the graph drawn to find:
(i) y1, the value of y, when x = 4.
(ii) y2, the value of y, when x = 0.
Find if the following points are collinear or not by using a graph:
(i) (-2, -1), (0, 3) and (1, 5)
(ii) (1, 3), (-2, -4) and (3, 5)
(iii) (2, -1), (2, 5) and (2, 7)
(iv) (4, -1), (-5, -1) and (3, -1)
