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प्रश्न
One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, the final temperature will be equal to ______.
(Cv = 20 JK−1)
विकल्प
150 K
100 K
26.85 K
295 K
MCQ
रिक्त स्थान भरें
उत्तर
One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, the final temperature will be equal to 150 K.
Explanation:
Work done during adiabatic expansion = Cv(T2 − T1)
or −3000 = 20(T2 − 300) ⇒ T2 = 150 K
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First Law of Thermodynamics
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