हिंदी

One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, the final temperature will be equal to ______. -

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प्रश्न

One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, the final temperature will be equal to ______.

(Cv = 20 JK−1)

विकल्प

  • 150 K

  • 100 K

  • 26.85 K

  • 295 K

MCQ
रिक्त स्थान भरें

उत्तर

One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, the final temperature will be equal to 150 K.

Explanation:

Work done during adiabatic expansion = Cv(T2 − T1)

or −3000 = 20(T2 − 300) ⇒ T2 = 150 K

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First Law of Thermodynamics
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