Advertisements
Advertisements
प्रश्न
One number is seven times another. If their difference is 18, find the numbers
उत्तर
Let the numbers be x & y
Given that one number is 7 times the other & that the difference is 18.
Let x = 7y
also, x – y = 18 ...(given)
Substituting for x in the above
We get 7y – y = 18
∴ 6y = 18
y = `18/6` = 3
∴ x = 7y = 7 × 3 = 21
The number are 3 & 21
APPEARS IN
संबंधित प्रश्न
Subtract the second expression from the first.
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract – 3ab – 8 from 3ab + 8. Also, subtract 3ab + 8 from – 3ab – 8
Subtract the following expressions:
–a2 – ab from b2 + ab
Subtract the following expressions:
x4 + 3x3y3 + 5y4 from 2x4 – x3y3 + 7y4
Subtract the following expressions:
–2a2 – 2b2 from –a2 – b2 + 2ab
How much is 21a3 – 17a2 less than 89a3 – 64a2 + 6a + 16?
To what expression must 99x3 – 33x2 – 13x – 41 be added to make the sum zero?
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
(A + B) – C
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
B + C – A
