हिंदी

P = αβ exp azKB(-azKBθ) θ → Temperature P → Pressure KB → Boltzmann constant z → Distance Dimension of β is ______. -

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प्रश्न

P = `alpha/beta` exp `(-"az"/"K"_"B"theta)`

θ `→` Temperature

P `→` Pressure

K`→` Boltzmann constant

z `→` Distance

Dimension of β is ______.

विकल्प

  • [M0 L0 T0

  • [M-1 L1 T2

  • [M0 L2 T0

  • [ML-1 T-2

MCQ
रिक्त स्थान भरें

उत्तर

P = `alpha/beta` exp `(-"az"/"K"_"B"theta)`

θ `→` Temperature

P `→` Pressure

K`→` Boltzmann constant

z `→` Distance

Dimension of β is [M0 L2 T0.

Explanation:

[P] = `[alpha]/[beta]`

[αz] = [KBθ ] = [PV]

⇒ [α] = MLT–2

[β] = `[alpha]/["P"]`

= L2

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