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प्रश्न
A spring-mass system oscillates with a frequency v. If it is taken in an elevator slowly accelerating upward, the frequency will
विकल्प
increase
decrease
remain same
become zero
उत्तर
remain same
Because the frequency ( \[\nu = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\]) of the system is independent of the acceleration of the system.
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