Question

P(x) = `{(1/"k" ((5),(x))"," (x=0,1,2,3,4,5); k > 0),(0 "," "otherwise"):},`

is p.m.f. of a r.v. X. Then `1/"k"` is equal to

विकल्प

• 16

• `1/16`

• `1/32`

• 32

Answer 1

`1/32`

Explanation:

X = x	0	1	2	3	4	5
P(X = x)	`1/"k"`	`5/"k"`	`10/"k"`	`10/"k"`	`5/"k"`	`1/"k"`

Since `sum_(x = 0)^5` P(X = x) = 1,

`1/k + 5/k + 10/k + 10/k + 5/k + 1/k = 1`

`=> 32/k = 1`

`=> 1/k = 1/32`