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प्रश्न
\[\begin{array}{cc}
\ce{Ph - CH - CH2 - CH2 ->[Zn - Cu][Δ] Product}\\
\phantom{..}|\phantom{......}|\phantom{....................}\\
\phantom{}\ce{Br}\phantom{....}\ce{Br}\phantom{..................}
\end{array}\]
Product of the above reaction is
विकल्प
Ph – CH = CH – CH2 – Br
Ph – Δ
Ph – CHBr – CH = CH2
Ph – C = C – CH3
MCQ
उत्तर
Ph – Δ
Explanation:
\[\ce{Zn -> Zn^{+2} + 2e-}\]
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